@ThinkCat 不太行
```
SELECT C.cno FROM C WHERE C.cno not in (SELECT DISTINCT SC.cno FROM S INNER JOIN SC ON S.sno=SC.sno WHERE S.sname=张三);
```
生成的 ast 树为
@Corybyte
```
&{{{{ SELECT C.cno FROM C WHERE C.cno not in (SELECT DISTINCT SC.cno FROM S INNER JOIN SC ON S.sno=SC.sno WHERE S.sname=张三); 0}}} 0xc000240390 false 0xc00017e300 0xc0002100c0 0xc0002403c0 [] [] false false 0 0 [] }
```
而我想拿到的结果为
```
SELECT C.cno FROM
SELECT DISTINCT SC.cno FROM S INNER JOIN SC ON S.sno=SC.sno WHERE S.sname=张三
```
